Let's analyze the clues given:

Clue 1 (9 2 8 5): one number is correct but wrongly placed.
Clue 2 (1 9 3 7): Two numbers are correct but wrongly placed.
Clue 3 (5 2 0 1): One number is right and well placed.
Clue 4 (6 5 0 7): nothing is correct.
Clue 5 (8 5 2 4): Two numbers are correct but wrongly placed.

From Clue 4, we know that 6, 5, 0, and 7 are not in the code.

Now let's start with Clue 3 since it tells us one number is correct and in the correct position, and the number can't be 5 or 0 due to Clue 4. So, the correct number in Clue 3 must be either 2 or 1. Since Clue 1 also has a 2 but in a different position, we can guess it's not the 2 that is correctly placed in Clue 3.

So we can assume that the number 1 is correct and in the right position in Clue 3, which means the code has 1 in the last position.

Looking at Clue 1 and Clue 5, since 5 and 8 cannot be in the code (5 ruled out by Clue 4, 8 would be in the wrong place in Clue 1 if it were correct), the number 2 must be correct but in the wrong place in both clues. Since 2 cannot be in the second or fourth positions (because 1 is correct in the fourth position), 2 must be in the first position of the code.

Now we have:
_ _ _ 1
2 _ _ _

From Clue 2, the numbers 1 and 9 cannot be correct because they are in the wrong positions (and we know 1 is in the fourth position). So the correct numbers from Clue 2 must be 3 and 7. But since 7 is incorrect from Clue 4, the correct number from Clue 2 can only be 3. It cannot be in the third position because that would make it correctly placed, so it must be in the second position.

So now we have:
2 3 _ 1

We need only find the third number. We know it's not 5, 6, 0, or 7 from Clue 4. It's not 1, 2, or 3 since those are already used. It's not 8 or 9 from Clue 1 (it would be in the wrong place). The only number left is 4. So the third number must be 4.

The code is:
2 3 4 1