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GPT-3.5-Turbo ·
Q: In pea plants, the trait for flower color is determined by a single gene with two alleles: purple (P) and white (p). If a heterozygous purple-flowered pea plant (Pp) is crossed with a homozygous white-flowered pea plant (pp), what is the probability of the offspring having purple flowers?
A: Let's think step by step.
Sure, let's break it down step by step.
First, we need to write out the genotypes of the parent plants:
- The heterozygous purple-flowered pea plant (Pp) has one P allele and one p allele.
- The homozygous white-flowered pea plant (pp) has two p alleles.
Next, we can set up a Punnett square to determine the possible genotypes of the offspring:
| p | p | |
|---|---|---|
| P | Pp | Pp |
| p | pp | pp |
| From the Punnett square, we can see that there are two possible genotypes for the offspring: Pp and pp. The Pp genotype corresponds to purple flowers, while the pp genotype corresponds to white flowers. | ||
| To determine the probability of the offspring having purple flowers, we need to look at the ratio of Pp genotypes to the total number of offspring. From the Punnett square, we can see that there are two Pp genotypes out of a total of four possible offspring. Therefore, the probability of an offspring having the Pp genotype and thus having purple flowers is 2/4 or 50%. | ||
| So, the probability of the offspring having purple flowers is 50%. |
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