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GPT-3.5-Turbo ·
In pea plants, the trait for flower color is determined by a single gene with two alleles: purple (P) and white (p). If a heterozygous purple-flowered pea plant (Pp) is crossed with a homozygous white-flowered pea plant (pp), what is the probability of the offspring having purple flowers?
The cross between a heterozygous purple-flowered pea plant (Pp) and a homozygous white-flowered pea plant (pp) can be represented by the following Punnett square:
| p | p | |
|---|---|---|
| P | Pp | Pp |
| p | pp | pp |
| Each box in the Punnett square represents a possible offspring. The probability of an offspring having purple flowers (Pp or PP) is the sum of the probabilities of the boxes that contain the P allele. In this case, there are two such boxes, with probabilities of 1/2 and 1/2. Therefore, the probability of an offspring having purple flowers is: | ||
| 1/2 + 1/2 = 1 | ||
| So, the probability of the offspring having purple flowers is 1 or 100%. This is because the P allele is dominant over the p allele, and a heterozygous plant (Pp) will always exhibit the dominant phenotype (purple flower). |
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