This is a logic puzzle where you need to deduce a 4-digit code based on clues given for each attempt. Here's how you can solve it:

1. Attempt 1 (9 2 8 5): It says one number is correct but wrongly placed. So one of these four numbers is correct but not in the position shown here.

2. Attempt 2 (1 9 3 7): Two numbers are correct but wrongly placed. So, two of these numbers are correct and also not in the positions shown here.

3. Attempt 3 (5 2 0 1): One number is right and well placed. Therefore, one of these numbers is correct and in the right position.

4. Attempt 4 (6 5 0 7): Here it states that nothing is correct, which means none of these numbers (6, 5, 0, 7) can be in the code.

5. Attempt 5 (8 5 2 4): Two numbers are correct but wrongly placed. So, two of these numbers are part of the code but not in the positions shown here.

Now, using the process of elimination and deduction:

• From attempt 4, we know that 6, 5, 0, and 7 cannot be in the code.
• From attempt 5, since 5 cannot be in the code, the numbers 8, 2, and 4 are the ones that are correct but wrongly placed.
• Since in attempt 3, the number 5 cannot be correct, it must be 2 that is correctly placed. Hence, the third digit is 2.
• From attempt 2, since 5 and 7 cannot be correct and we've placed 2 in the third position, the correct numbers must be 1 and 9. Since they are wrongly placed in this attempt, 1 cannot be the first digit and 9 cannot be the second digit.
• From attempt 1, 9 or 5 could be the correct but wrongly placed digits; however, since 5 is not in the code (from attempt 4), and 9 must be the correct number but cannot be in the second position (from attempt 2), it must be in the fourth position. This also confirms that the second number cannot be 2 (since it's in the third slot), 8, or 5, leaving only 4 as an option for the second digit.
• The only number left for the first position is 1.

Therefore, the code is 1 4 2 9.